-16n^2-72n-80=0

Solution for -16n^2-72n-80=0 equation:

-16n^2-72n-80=0

a = -16; b = -72; c = -80;
Δ = b2-4ac
Δ = -722-4·(-16)·(-80)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8}{2*-16}=\frac{64}{-32}
=-2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8}{2*-16}=\frac{80}{-32}
=-2+1/2
$